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a lady gives a dinner party to six guests. the number of ways in which they may be selected from among ten friends, if two of the friends will not attend the party together is ?

Case I : Both of them don't attend the party.then, no of ways = 8C6 = 28Case II : Either of them is selected for party.then, no of ways = 2C1 * 8C5 = 112Total no of ways = 112+28 = 140
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Case I : Both of them don't attend the party.then, no of ways = 8C6 = 28Case II : Either of them is selected for party.then, no of ways = 2C1 * 8C5 = 112Total no of ways = 112+28 = 140
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total no of ways to select 6 frm 10=10C6=210
total ways of selecting the 2 always = 2C2*8C4=70
so req no ways = 210 - 70 = 140    


 
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otal no of ways to select 6 frm 10=10C6=210
total ways of selecting the 2 always = 2C2*8C4=70
so req no ways = 210 - 70 = 140 ? ?


?
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140
 
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