A large mass 'M' moving with a velocity 'v' collides head-on with a very small mass 'm' at rest. If the collision is elastic, obtain an expression for the energy lost by the large mass M (take M+m=M) Share with your friends Share 7 Ved Prakash Lakhera answered this According to law of conservation of momentum, MV=M+mV1 V1=MVM+mAccording to law of conservation of energy, 12MV2=12M+mV12Energy of larger mass=12MV12=12MMVM+m2=12M3V2M+m2Now the loss of energy of larger mass ∆E=12MV2-12M3V2M+m2=12MV2M2+m2+2Mm-M2M+m2 Therefore ∆E=12MV2mm+2MM+m2=12mm+2MMV2 2 View Full Answer Ankita Gaur answered this No answer yet.. -17