# A lending library has a fixed charge for the first three days and an additional charge for each day thereafter. Saritha paid Rs 27 for a book kept for seven days, while Susy paid Rs 21 for the book she kept for five days. Find the fixed charge and the charge for each extra day.

let fixed charge = Rs. x .... additional charge = Rs. y ....

For Saritha :- Rs (x + 4y) = Rs. 27

----> x + 4y = 27 ..... (I) ....

For Susy :- Rs. (x + 2y) = Rs. 21

----> x + 2y = 21 .... (II) ...

Solving both equations :-

2y = 6 --- > y = 3 .....

x = 21 - 2y  [from (II)] ...

----> x = 21 - 6 = 15 ....

Hence, fixed charge for first three days = Rs. 15 ..... (ans) ...

and additional charge for each day = Rs. 3 .... (ans) ...

Hope this helps !!!

• 79

let fix charg be x and aditional charge be y

so 1st eq is :- 3x + 4y = 27

and 2nd eq is :- 3x+ 2y = 21

frm eq 1 x= 27-4y / 3

putin this valu in eq in eq 2 we get

27- 4y +2y= 21

so y = 3

and x= 5

hope this helps

if yes then pls thumbs up

• 27

here x= 5 means that fixed charge for one day was Rs 5

that means fixed charge for three days was Rs 15

and additional charge for each day was Rs 3

hope it helps

thumbs up pls......:)

• -5

u need to find the fixed price of first 3 dayzz ....... not each day !!

• -2

oops sorry ... I didn't see the correction !!

• -7

x [cost of three days] + y [cost of 1 additional day] + y +y+y = 27

15 +3+3+3+3 = 27

That was very simple .

• -7

Let the fixed charge be Rs.'x' and additional charge be Rs 'y'

Charges for Saritha--> x+4y=27 ----(1)

Charges for Susy ---> x+2y=21 ----(2)

Solution of equation (1) and (2),

x+4y=27

=> x=(27-4y) -----(3)

Substituting the value of x in equation (2), we get,

x+2y=21

=> 27-4y+2y=21

=> 27-21= 4y-2y

=> 6= 2y

=> 3=y

x=27-4y (From 3)

x= 27-4*3

=> x= 27-12

=> x=15

Therefore Value of x is 15 and y is 3.

Hence Required Answer---> Fixed Charge for first three days= x= Rs15

Additional Charge Per Day= y= Rs 3

• 0
 Let the fixed charge be Rs.'x' and additional charge be Rs 'y' Charges for Saritha--> x+4y=27 ----(1)      Charges for Susy ---> x+2y=21 ----(2) Solution of equation (1) and (2), x+4y=27 => x=(27-4y) -----(3) Substituting the value of x in equation (2), we get, x+2y=21 => 27-4y+2y=21 => 27-21= 4y-2y => 6= 2y => 3=y x=27-4y (From 3) x= 27-4*3 => x= 27-12 => x=15  Value of x is 15 and y is 3 Hence Required Answer---> Fixed Charge for first three days= x= Rs15                                                  Additional Charge Per Day= y= Rs 3

• 19

Hope this helps ! ! ! !

YOU................

• -6

Nopes this one wud neve

• -6

oe dhoni  abhi too jinda hai

• -3

Hi!
sAtyAjit_994 correctly answered the question.
m_s_dhoni correctly answered the question.
anuragdon111...  correctly answered the question.

Good effort!
Your answers are really helpful to all the users of this community.
Keep writing!!!

Cheers!

• 4

from where the 4y comes

• -6
What are you looking for?