A letter 'A' is made with uniform wires of resistance 1 ohm.The sides of the letter are each 20 cm long & the middle piece is 10 cm.If the apex angle is 60 degree find the resistance of the letter between the ends of its legs.

Current will pass through the loop BDECB.

Net resistance = R (of BD) + R (of DE) + R (of DC)

 = 3R  (R is the resistance of each section.)

Equivalent resistance has length of wire 30cm.

Resistance of wire 1 ohm has length of 50cm ((20+20+10) cm). 

Resistance of 30cm wire = (1/50)*30 = 0.6 ohm

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