A liquid 'X' at temperature 40 degree C of specific heat capacity 0 84 J/gK is mixed with another liquid - Physics - Heat

Question

A liquid 'X' at temperature 40 degree C of specific heat capacity 0
84 J/gK is mixed with another liquid 'Y' at 20 degree C of S H C 2
1 J/gK such that the final temperature of mixture becomes 32 degree
C What mass of liquid 'X' is mixed if mass of liquid 'Y' is 100 g?

Jyoti Pant · Accepted Answer

m1=?m2=100 g∆T1=400-320=80s1=0
84 J/gK∆T2=320-200=80s2=2
1 J/gKNow,Heat lost by X=Heat gained by Ym1s1∆T1=m2s2∆T2m1×0
84×8=100×2 1×8or m1=250 g

A liquid 'X' at temperature 40 degree C of specific heat capacity 0.84 J/gK is mixed with another liquid 'Y' at 20 degree C of S.H.C.2.1 J/gK such that the final temperature of mixture becomes 32 degree C .What mass of liquid 'X' is mixed if mass of liquid 'Y' is 100 g?