A long metallic wire is bent in form of a triangle. The sides of this triangle were 3xy+ 4x2y, 4xy2-3x2y, 2xy2+2xy. Find the length of the triangle. Share with your friends Share 8 Varun.Rawat answered this Let ABC be the ∆.Let AB = 3xy + 4x2yLet BC = 4xy2-3x2yLet CA = 2xy2 + 2xyNow, perimeter of ∆ABC = AB + BC + CA=3xy + 4x2y + 4xy2-3x2y + 2xy2 + 2xy=3xy + 4x2y+4xy2-3x2y+2xy2+2xy=5xy+x2y+6xy2 1 View Full Answer V Sharmila answered this I don't know the answer -3