A long straight wire, carrying current I , is bent on its midpoint to form an angle of 45 degrees . Find the induction of magnetic field at point P, distant R from the point of bending

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Since the point P lies on the axis of straight part OA, magnetic field at point P is zerodue to a part OA of wire.For part OC, from OPN,d=R cos45°Since both the ends O and C are on the same side of the normal PN, therefore,ϕ1=-45° and ϕ2=90°So, B=μ0i4πdsin ϕ1+sin ϕ2 B=μ0i4πR cos45°sin-45°+sin90° B=μ0i×24πR-sin45°+1 B=2μ0i4πR1-12 B=2μ0i4πR2-12 B=μ0i4πR2-1

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