A loss free transformer having 100 turns in a primary is used to transmit 10kW of power. The input voltage is 200V and Power is transmitted at 5kV. The currents in the primary and secondary of the transformer are
A) 2 A and 50 A
B) 50 A and 2 A
C) 25 A and 4 A
D) 12.5 A and 8 A
Would appreciate it if you could give a detailed explanation and solution.

Correct option (b)
Here,np=100P=5kW=5×103 WEp=200VEs=5000VP=104WSince the transformer is lossless power input = power outputSo, P=EpIp=>Ip=PEp=104200=50AAgain since the transformer is losslessoutput power = input power=>EsIs=P=>EsIs=104=>Is=1045000=2So current in primary = 50 A and current in the secondary = 2A

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