A luminescent object is placed at a depth d in a optically denser medium of refractive index . Prove that radius r,of base of cone of light , from the object that can emerge out from the surface, r=d/√(r^2-1)

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Hey correct ur que
Below its mu not r^2
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  1. A luminescent object is placed at a depth ‘d’ in a (optically) denser medium of refractive index ‘µ’. Prove that radius r, of the base of the cone of light, from the object, that can emerge out from the surface, is  .
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Proof

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What are you looking for?