a man 1.5m tall walks away from a lamp post 4.5m high at the rate of 4km/hr.
  • how fast the farther end of the shadow moving on the pavement

take tan x =height of man /size of shadow 
and tan x=height of lamp/size of shadow + distance between man and lamp

then equate it.....you will get the answer as 2km/h
  • -17
Ghhh
  • 0
That's the ans

  • 13
Kundan that would be the ans to rate of change length of shadow
  • 2
Pr dx/dt 4000 kaise aaya??
  • 0
What are you looking for?