a man 1.5m tall walks away from a lamp post 4.5m high at the rate of 4km/hr.
- how fast the farther end of the shadow moving on the pavement
take tan x =height of man /size of shadow
and tan x=height of lamp/size of shadow + distance between man and lamp
then equate it.....you will get the answer as 2km/h
and tan x=height of lamp/size of shadow + distance between man and lamp
then equate it.....you will get the answer as 2km/h