a man borrows Rs 12000 at a certain rate of compound interest per annum,his loan becomes Rs12730 80 at the - Maths - Compound Interest

Question

a man borrows Rs 12000 at a certain rate of compound interest per
annum,his loan becomes Rs12730 80 at the end of 2 years
1)find the principal in the beginning of the second year
2)find the compound interest(to the nearest rupee)on the sum for 3
years

Koka Sri Lakshmi Divya Sai · Accepted Answer

Dear Student

Given Principal for the first year =Rs
12000Amount after 2 years = Rs 12730
80Hence n=2 Let the rate interesr =r%We know thatA=P1+r100n⇒12730
80=120001+r1002⇒12730 8012000=1+r1002⇒1+r1002=1
0609⇒1+r100=1 03⇒r100=0
03⇒r=3%(i)Interest at the end of 1st yearI=PTR100  =12000×1×3100=360Pricipal in the beginning of 2nd year=P+I                                                                   =12000+360                                                                    =Rs
12360(2)Compound interest on the sum of 3 yearsA=P+1+r1003    =120001+31003    =120001
033    =12000×1
092727    =Rs 13112 70C
I on the sum of 3 years=Rs 13112
70-12000                                                                =Rs
1112 70 
Regards

a man borrows Rs 12000 at a certain rate of compound interest per annum,his loan becomes Rs12730.80 at the end of 2 years. 1)find the principal in the beginning of the second year 2)find the compound interest(to the nearest rupee)on the sum for 3 years

a man borrows Rs 12000 at a certain rate of compound interest per annum,his loan becomes Rs12730.80 at the end of 2 years.
1)find the principal in the beginning of the second year
2)find the compound interest(to the nearest rupee)on the sum for 3 years