A man bought a number of oranges at 3 for a rupee and an equal number of oranges at 2 - Maths - Comparing Quantities

Question

A man bought a number of oranges at 3 for a rupee and an equal
number of oranges at 2 for a rupee At what price per should he sell
them to make a profit of 20%?

Manbar Singh · Accepted Answer

A man bought 2 kinds of oranges : one at the rate of 3 for a rupee and other at the rate of 2 for a rupee
Since it is given that he bought equal number of oranges of both types, soLet the number of oranges bought of each kind = 6Cost of 3 oranges of first type = Re 1
00Cost of 6 oranges of first type = Rs 13×6 =Rs 2
00cost of 2 oranges of second type = Re 1
00Cost of 6 oranges ofsecond type = Rs 12×6 =Rs 3
00So, total cost of 12 oranges, CP = Rs 2
00+3 00 =Rs 5
00Now, profit % = 20%⇒profitCP×100% = 20%⇒5profit = CP⇒5SP - CP = CP⇒5SP - 5 =5⇒5SP - 25 = 5⇒5SP = 30⇒SP = Rs 6
00So, SP of 12 oranges = Rs 6
00SP of 1 orange = Re612 = Re 0
50 = 50 paise

A man bought a number of oranges at 3 for a rupee and an equal number of oranges at 2 for a rupee. At what price per should he sell them to make a profit of 20%?