a man of mass m stands on a platform of equal mass m and pulls himself by two ropes passing over pulleys. If he pulls each rope with a force equal to half its weight, his upward acceleration will be?

Dear Student,

The downward force, f=mg+mg=2mgTension in the string, T'=T+T=2TTension, T applied by the man=122mg=mgHence, total force, f'=2×mg=2mgSo, the net force on the system, F=2mg-2mg=0Hence, acceleration=0

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