a man starts walking from home at the rate of 3km/hr. and reaches a place due north in 2 hrs. and from A he walks due east and reaches a place in 2hrs. 40 mins. in what time can he walk straight from home to B at the same rate ?

Dear Student,

Let the man starts from house H and moves north to A and then moves east to B. Speed of man=3km/hr.Time taken to travel from H to A=2 hoursThus, distance between H and A=HA=32=6 kmTime taken to travel from A to B=2 hours 40 minutes=24060hours                                                          =223hours=83hoursThus, distance between A and B=AB=383=8 kmBy pythagoras theorem in HAB,HB2=HA2+AB2HB2=62+82HB2=36+64=100HB=10 kmThus time taken to travel from H to B=103hours=313hours                                                               =32060hours= 3 hours 20 minutesTime taken by man if he walks straight from home to point B=3hours 20 minutes

Hope this information will clear your doubts about topic.

If you have more doubts just ask here on the forum and our experts will try to help you out as soon as possible.

Regards

  • 4
experts plss. ansr.
  • 4
i forget the answer
  • 0
What are you looking for?