A man with blue eyes and black hair (homozygous for both characters) marries a woman with
black eyes and red hair. Black eyes (E) are dominant over blue eyes (e) and black hair (H) is dominant over red hair (h). Work out the probabilities of phenotypes of the children of this couple using punnett square method.
The man with blue eyes and black hair will have the genotype eeHH (as homozygous for both characters) while the woman with black eyes and red hair may have the genotype EEhh or Eehh. Let's first consider her to be EEhh. Then their progeny genotypes can be calculated as follows:
Thus, all their progeny will have black eyes and black hair. The probability of phenotypes of the progeny in second case can be worked out in a similar manner.
| Eh | Eh | |
|---|---|---|
| eH | EeHh | EeHh |
| eH | EeHh |
EeHh |
Thus, all their progeny will have black eyes and black hair. The probability of phenotypes of the progeny in second case can be worked out in a similar manner.