Explanation:
CUBE = 2cm = 2/100 m = 2*10^-2m
Given, length of cube, l = 2*10^-2m
Volume V = l^3 = 8*10^-6m
Let's, density = p (sorry, it's raw not P I'm taking p)
then, Mass = p*v
M = p*8*10^-6*10
= p*8*10^-3
therefore, 0.56 = p*8*10^-6*10
= p*7*10^3 kg m^-3
Therefore, Density of material p= 7*10^3 kg m^-3
when it is submerged in a liquid with density P(L), it's apparent weight reduces due to Buoyant Force on it
Buoyant force N= P(L) Vg
Given, P(L) = 0.85g cm^-3
= 0.85*10^3 kg m^-3
N = 0.85 * 10^3 * 8 * 10^-6 * 10
= 68 * 10^-3 N
= 0.068 N
Apparent weight W1 = W-N
= (0.56-0.068) N
= 0.492 N
