A metal cube of edge 12 cm is melted and formed into three smaller cubes. If the edge of the two smaller cubes are 6 cm and 8 cm, find the edge of the third smaller cube. Pls solve this question
Dear student,
Let the edge of the other cube be 'a'.
Given, 123=b3+83+a3 (volume remains the same)
a3=123−63−83
a3=1728−216−512
a3=1000
a=10
Edge of the cube = 10 cm.
Regards
Let the edge of the other cube be 'a'.
Given, 123=b3+83+a3 (volume remains the same)
a3=123−63−83
a3=1728−216−512
a3=1000
a=10
Edge of the cube = 10 cm.
Regards