A metal cube of side 10 cm is subjected to a shearing stress of 10 raise to 4 N/m square - Physics - Mechanical Properties Of Solids

Question

A metal cube of side 10 cm is subjected to a shearing stress of 10
raise to 4 N/m square calculate the modulus of rigidity if the top
of the cube is displaced by 0 05 cm with respect to its bottom

Jyoti Pant · Accepted Answer

Given,
Length of side, L=10 cm=0
1 mShearing stress, F=104N/m2Shearing displacement, ∆x=0
05 cm=0
0005 mNow, the modulus of rigidity is given as,η=FA
θ=F LA
∆x[θ≃tanθ=∆xL]So, η=104×0
10 0005=2×106N/m2

A metal cube of side 10 cm is subjected to a shearing stress of 10 raise to 4 N/m square . calculate the modulus of rigidity if the top of the cube is displaced by 0.05 cm with respect to its bottom