A metal has BCC structure and edge length of it's unit cell is 3.04A. the volume of the unit cell in cm will be

Dear Student,
GIVEN: a=3.04 angstroms =2.04×10-8cm
 BCC structure so Z=2 ,
d=Z×Ma3×NA
we know that d= MV
putting this value in the first equation we get
MV=Z×Ma3×NA
cancelling M on both sides we get
V=a3×NAZ
putting the given values in the above equation we get
V=(3.04×10-8)3×6.023×10232
V= 8.46 cm3


 

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