A metal oxide has the formula Z2O3 . It can be reduced by hydrogen to give free metal and water . 0.16 gm of the metal oxide requires 6 mg of hydrogen for complete reduction. The atomic weight of a metal is:
Given,
Metal oxide has the formula Z2O3
Valency of the metal in Z2O3 = 3
Z2O3 + 3H2 → 2Z + 3H2O
As 0.16 g of Z2O3 reacts with H2 = 6 mg = 0.006 g
So, 1 g of H2 react with 0.16/0.006 = 26.67 g of Z2O3
Hence,
Equivalent weight of Z2O3 = 26.67
Equivalent weight of Z + Equivalent weight of O = E + 8 = 26.67
Therefore,
Equivalent weight of Z = 26.67 - 8 = 18.67
Hence,
Atomic weight of Z = 18.67 x 3 = 56.01
Metal oxide has the formula Z2O3
Valency of the metal in Z2O3 = 3
Z2O3 + 3H2 → 2Z + 3H2O
As 0.16 g of Z2O3 reacts with H2 = 6 mg = 0.006 g
So, 1 g of H2 react with 0.16/0.006 = 26.67 g of Z2O3
Hence,
Equivalent weight of Z2O3 = 26.67
Equivalent weight of Z + Equivalent weight of O = E + 8 = 26.67
Therefore,
Equivalent weight of Z = 26.67 - 8 = 18.67
Hence,
Atomic weight of Z = 18.67 x 3 = 56.01