A metallic wire 1m in length is moving normally across a field of 0.1 T with a speed of 5 ms-1 find the emf between the ends of the wire.

emf, e = B l vGiven , B = 0.1 T v =5 ms-1l = 1 mSo emf produced ,e = 0.1×5×1 = 0.5 V

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