A mixed doubles tennis game is to be played between 2 teams(each team consists of 1 male & 1 female).There are 4 married couples.No team is to consist of a husband & a wife.What is the maximum number of games that can be played? : options are :

a 12 , b 21 , c 36, d 42 [IAS 2006]

my approach gives answer as 66 in this way: Let A,B ,C and D are 4 males . A can make team with other 3 females in 3 ways.Similarly B can make team with other 3(except his wife say X) females in 3 ways.Similarly C & D will make 3 teams each , making it a total of 4*3 =12 teams.Now , Question becomes like 12 teams can be arranged in how many ways ?

It is = 12C2 (because 1 GAME needs 2 TEAMS)

=12!/ 2! *10! = 66 GAMES . But, this is not in the options. Plz help me finding out the error I committed and provide me the right solution soon.