A mixture has 18g water and 414g ethanol. What are the mole fraction of water and ethanol?

Dear student

Weight of H₂​O=18g
Molecular weight of H₂​O=18u
∴ Moles of H₂​O=18 / 18​=1
Weight of ethanol (C₂​H₅​OH)=414g
Molecular weight of C₂​H₅​OH=46u
∴ Moles of C₂​H₅​OH=46 / 414​=9
∴ Mole fraction of water =moles of H₂​O / moles of H₂​O +moles of C₂​H₅​OH
=1 / (1 + 9)
∴ Mole of fraction H₂​O=0.1