A mixture of SO2 and O2 at 1 arm in the mole ratio 2:1 is passed through catalyst at 1170C - Chemistry - Chemical and Ionic Equilibrium

Question

A mixture of SO2 and O2 at 1 arm in the mole ratio 2:1 is passed
through catalyst at 1170C at a rate sufficient for attainment of
equilibrium The existing gas suddenly chilled and analysed is found
to contain 87% SO3 by volume Calculate kp for the reaction
SO2+1/2O2--->SO3

Rahul Yogi · Accepted Answer

Dear student,

Since mole fraction is pressure fraction,
Hence pressure of SO2 is 2/3 and pressure of
O2 is 1/3

SO2       +       12O2   →        SO3             23-x            13-x2               xAccording to question,x23-x+13-x2+x=0
87On solving we get x =0
60            
Putting the values in the expression of Kp

Kp = x23-x13-x212Putting the value of x calculated and solving,we get,Kp = 48
2 (atm)-0 5
Hope this helps,
Regards

A mixture of SO2 and O2 at 1 arm in the mole ratio 2:1 is passed through catalyst at 1170C at a rate sufficient for attainment of equilibrium. The existing gas suddenly chilled and analysed is found to contain 87% SO3 by volume. Calculate kp for the reaction SO2+1/2O2--->SO3