A monoenergetic (18 keV) electron beam initially in the horizontal direction is subjected to a horizontal magnetic field of 0.04 G normal to the initial direction. Estimate the up or down deflection of the beam over a distance of 30 cm (me= 9.11 × 10−19 C). [Note Data in this exercise are so chosen that the answer will give you an idea of the effect of earth’s magnetic field on the motion of the electron beam from the electron gun to the screen in a TV set.) in this question in the circled step how do we multiply 10^-15 pls explain no links pls

A monoenergetic (18 keV) electron beam initially in the horizontal direction is subjected to a horizontal magnetic field of 0.04 G normal to the initial direction. Estimate the up or down deflection of the beam over a distance of 30 cm (me= 9.11 × 10−19 C). [Note Data in this exercise are so chosen that the answer will give you an idea of the effect of earth’s magnetic field on the motion of the electron beam from the electron gun to the screen in a TV set.) in this question in the circled step how do we multiply 10^-15 pls explain no links pls Solution Energy of an electron beam, E = 18 kev Charge on an electron, e = 1.6 x 10 19 C 18 103 x 1.6 x J Magnetic field, B = 0.04 G 18 x 103 ev Mass of an electron, me = 9.11 x 10¯19 kg Distance up to which the electron beam travels, d 30 cm = 0.3 m We can write the kinetic energy of the electron beam as: E = — ntv2 2 m 2 x 18 x 108 x 1.6 x 10-1 9.11 x IO- 101 0.795 x 108 m/s The electron beam deflects along a circular path of radius, r. The force due to the magnetic field balances the

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