A MOTOR BOAT WHOSE SPEED IS 20KM/H IN STILL WATER, TAKES 1 HOUR MORE TO GO 48 KM UPSTREAM THAN TO RETURN DOWNSTREAM TO THE SAME SPOT FIND THE SPPEED OF THE STREAM

IF THE ROOTS OF THE EQ (a^{2} +b^{2})x^{2} - 2(ac+bd)x + (c^{2}+d^{2})c = 0 EQUAL PROVE THAT a/b = c/d

Velocity of boat in still water(v) = 20 km/hr

Let the velocity f the stream be x km/hr

So velocity of the boat during upstream is (20-x) km/hr

Velocity of the boat during downstream is (20+x) km/hr

So according to the question

Neglect the negative value.

So the velocity of the stream is 4 km/hr.

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