a motor pump lifts water from an average dept of 15m at the rate of 5kg per second. if the water is coming out of the pump with a velocity of 4ms-1, the power of the motor is? ( g= 10ms-1) (ans : 790W) Share with your friends Share 0 Ved Prakash Lakhera answered this Let the power of the engine is P,Therefore P=mt×g×h + 12mv2=5×10×15 + 12×5×4×4or P=750 + 40 = 790W 1 View Full Answer