a N2 and H2 mixture initially in a molar ratio 1:3 reached equilibrium to form NH3 when 25% of N2 and H2 reacted. If total pressure of system was 21atm. The partial pressure of NH3 at equilibrium is a N2 and H2 mixture initially in a molar ratio 1:3 reached equilibrium to form NH3 when 25% of N2 and H2 reacted. If total pressure of system was 21atm. The partial pressure of NH3 at equilibrium is Share with your friends Share 45 Vartika Jain answered this Dear Student, N2 + 3H2 → 2NH3 a 3a 0Since 25% of the material has reacted,Therfeore, total number of moles at equilibrium = a-a4+3a-3a4+2a4=7a2Partial pressure of ammonia at equilibriumpNH3=Moles of NH3×Total pressureTotal number of molesor, pNH3=2a47a2×21= 17×1= 3atm 58 View Full Answer