a N2 and H2 mixture initially in a molar ratio 1:3 reached equilibrium to form NH3 when 25% of N2 and H2 reacted. If total pressure of system was 21atm. The partial pressure of NH3 at equilibrium is a N2 and H2 mixture initially in a molar ratio 1:3 reached equilibrium to form NH3 when 25% of N2 and H2 reacted. If total pressure of system was 21atm. The partial pressure of NH3 at equilibrium is

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N2 +   3H2  2NH3 a          3a             0Since 25% of the material has reacted,Therfeore, total number of moles at equilibrium = a-a4+3a-3a4+2a4=7a2Partial pressure of ammonia at equilibriumpNH3=Moles of NH3×Total pressureTotal number of molesor, pNH3=2a47a2×21= 17×1= 3atm

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