# a natural number is chosen at random from among the first 500. what is the probability that the number chosen is divisible by 3 or 5

**233/500**This may not be the textbook method, but it sure works:

*Number of possible outcomes for a number…*

__Divisible by 5__: 500 / 5 =

*100*numbers

__Divisible by 3__: 500 / 3 = 166.66 ≈

*166*numbers

__Divisible by both 3 and 5 (i.e. 15)__: 500 / 15 = 33.33 ≈

*33*numbers

__Divisible by either 3 or 5__:

*(100 + 166) – 33 = 233*numbers

Probability the number chosen being divisible by 3 or 5:

**233 / 500**