A nucleus with mass number A=220 decays by a-emission the energy released is 5 5 MeV, a god estimate - Physics - Nuclei

Question

A nucleus with mass number A=220 decays by a-emission the energy
released is 5 5 MeV, a god estimate for the kinetic energy of the
a-particle will be-

4 4 MeV
5 4 MeV
​5 6 MeV
6 5 MeV

Rupak Bhattacharya · Accepted Answer

supposeA220→B216+αnow net enrgymBv2B2+mαv2α2=5
5 MeVusing the momentum conservation relation mBvB=mαvα we can get(1+mαmB)×K
Eα=5 5 MeVK Eα=5 5(1+mαmB)=5 51+4216≈5
4MeV   [ANS]

A nucleus with mass number A=220 decays by a-emission. the energy released is 5.5 MeV, a god estimate for the kinetic energy of the a-particle will be- 4.4 MeV 5.4 MeV ​5.6 MeV 6.5 MeV

A nucleus with mass number A=220 decays by a-emission. the energy released is 5.5 MeV, a god estimate for the kinetic energy of the a-particle will be-

4.4 MeV

5.4 MeV

5.6 MeV

6.5 MeV