a number consists of two digits whose sum is 8. If 18 is added to the number, its digits are reveresed. Find the number.
can anyone has the solution to it??? i could not get it...please help me
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Let the ten's digit of the no.be x and the unit's digit be y.
10x+y+18=10y+x(as the digits het reversed)
9x-9y=-18=>x-y=-2(dividing all the terms by 9)
Now we have a pair of simultaneous linear equations.
x+y=8 and x-y=-2.
Solve them.You'll get x=3 and y=5.
Thus the number =10x+y=35.
if we add 18 to the number, ie 10x+y+18
10x+ y +18 = 10y+ x
9x + y + 18 = 10y
x - y = -2
So we have 2 equations:
solve these to give x=3 and y=5 ie we had 35 and 53.