A number is selected at random from first 50 natural numbers. Find the probability that it is a multiple of 3 and 4.

Total number of outcomes = 50

Let E be the event of getting a number which is a multiple of 3 and 4.

Now, the common multiples of 3 and 4 among first 50 natural numbers are 12, 24, 36 and 48.

So, the favourable number of outcomes are 4.

∴ Required probability = P(E) = $\frac{\mathrm{Favourable} \mathrm{number} \mathrm{of} \mathrm{outcomes}}{\mathrm{Total} \mathrm{number} \mathrm{of} \mathrm{outcomes}}=\frac{4}{50}=\frac{2}{25}$