A number is selected at random from the number 9,9,7,7,5,9,3,5,7,9. The probability that the selected number is their average is :

(a) 9/10

(B)7/10

(C)3/10

(d)1/10

The given number are 9, 9, 7, 7, 5, 9, 3, 5, 7 and 9.

∴ Total number of outcomes = 10

Average of the given numbers

Let A denote the event that the selected number is the average of the given number.

There are three outcomes in favour of event A i.e.,  7, 7 and 7.

Total number of favourbale outcomes = 3

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answer is (C) 3/10

average is = (9+9+7+7+5+9+3+5+7+9)/10 

                   = 7

probablity = no. of 7 s / total no. of numbers =3/10

  • 1
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