a number X is selected at random from the numbers 1,4,9,16 and another number y is selected at random from the numbers 1,2,3,4. find the probability that the value of xy is more than 16.

No. of possible outcomes = 8
Total number of outcomes = 4*4 = 16
P(A) = 8/16 = 1/2
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I am sorry... this answer was for product less than 16
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No. of possible outcomes = 6
Total no. of outcomes = 4*4 = 16
P(A) = 6/16 = 3/8
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i dont think this answer is correct
 
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Plzzzz give me a correct answer.. .
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Are repeated outcomes considered???or eXcluded???
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is it
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The answer is 9/16 not 8/16 or 6/16
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8/16 = 1/2 
 
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Hope this helps!

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This is the answer~

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This is the answer~

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The correct answer is 3 by 8 because it is given that the value should be greater than 16 not equal to 16 so correct answer is 3 by 8 not 1 by 2
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