A,O,B are 3 points on a line segment and C is a point not lying on AOB if angle AOC = 40 and OX ,OY are the internal and external bisections of angle AOC respectively then angle BOY is ??? Share with your friends Share 0 Neha Sethi answered this Dear student Since ∠AOC=40°So, ∠BOC=∠AOC=180° [Linear pair]⇒∠BOC=180°-40°⇒∠BOC=140°Since OY is external bisector of ∠AOCSo, ∠COY=∠BOYand ∠BOC=∠COY+∠BOY⇒∠BOC=2∠BOY⇒140°=2∠BOY⇒∠BOY=70° Regards 3 View Full Answer Anshu answered this by exterior angle property. 0