A,O,B are 3 points on a line segment and C is a point not lying on AOB if angle AOC = 40 and OX ,OY are the internal and external bisections of angle AOC respectively then angle BOY is ???

Dear student

Since AOC=40°So, BOC=AOC=180°   [Linear pair]BOC=180°-40°BOC=140°Since OY is external bisector of AOCSo, COY=BOYand BOC=COY+BOYBOC=2BOY140°=2BOYBOY=70°

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by exterior angle property.
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