A pack of cards contains 4 aces, 4 kings , 4 queens and 4 jacks. Two cards are drawn at random from this pack without replacement . What is the probability that atleast one of them will be an ace ? Share with your friends Share 4 Shrutika Pedamkar answered this P(at least 1ace)=1-P(no ace) =9/20 4 View Full Answer Anaya answered this Thank you very much but could you plz elaborate the answer ? Could you plz write the steps ? Thank you ! 0 Shrutika Pedamkar answered this P(no ace)=12C2/16C2 =12*11/16*15 =11/20 P(at least one ace) =1-P(no ace) =1-11/20 =9/20.... :D 7