A pack of cards contains 4 aces, 4 kings , 4 queens and 4 jacks. Two cards are drawn at random from this pack without replacement . What is the probability that atleast one of them will be an ace ?

P(at least 1ace)=1-P(no ace)
=9/20
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Thank you very much but could you plz elaborate the answer ? Could you plz write the steps ? Thank you !
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P(no ace)=12C2/16C2 =12*11/16*15 =11/20
P(at least one ace) =1-P(no ace) =1-11/20 =9/20.... :D
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What are you looking for?