A pair of die is thrown. Find the probability of getting a sum of 10 or more if 5 appears on the first die. pls give answer step by step.
Dear Student
In throwing a dice, total possible outcomes = {1, 2, 3, 4, 5, 6}
n(S) = 6
For two dice, n(S) = 6 x 6 =36
Favourable cases where sum is 10 or more with 5 on first dice {(5,5), (5,6)}
Event of getting sum is 10 or more with 5 on first dice = n(E) = 2
Probability of getting sum of 10 or more with 5 on first dice = n(E)/n(S) = 2/36 = 1/18
Regards
In throwing a dice, total possible outcomes = {1, 2, 3, 4, 5, 6}
n(S) = 6
For two dice, n(S) = 6 x 6 =36
Favourable cases where sum is 10 or more with 5 on first dice {(5,5), (5,6)}
Event of getting sum is 10 or more with 5 on first dice = n(E) = 2
Probability of getting sum of 10 or more with 5 on first dice = n(E)/n(S) = 2/36 = 1/18
Regards