A pan filled with hot food cools from 94 degrees to 86 degrees in 2 minutes when the room temperature is at 20 degrees Celsius.How long will it take to cool from 71 degrees to 69 degrees Celsius??

For the first caseTavg = 94+862 = 90o Cwhich is T=70oC above the room temperature.From newton's law of cooling we have,dTt = -K×T        (-ve sign implies the slope of the curve is -ve)Thus,neglecting the -ve signdTt = K×T82 = 70×KK = 82×70 ----- (1)Now,For the second caseTavg = 69+712 = 70oCT = 70-20 =50 oCNow,dT = 2thus,2t' = K × 50t' = 2K × 50 = 282×70×50=0.7 mint' =0.7×60 =42 secs

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