a particle 'A' starts moving from a point A with constant velocity 6m/s along x axis Another particle B initially at rest starts moving along x axis after 8/3 sec after the start of A with an acceleration varying as a=4m/s^2 the time when two particles meet if they are moving in the same line meritnation experts plz don't ask to refer the question asked by priyal as the answer stated by the expert is not at all appropriate plz answer my question

Dear Student,

Please find below the solution to the asked query:

Suppose they will meet at time t after B starts. Now in this time A will move by distance t+836. and by this time B will travel 12×4×t2=2t2So we have2t2=6t+162t2-6t-16=0t=4.7, -1.7 s. So the two particle will starts at 4.7 s after B starts moving. 

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