​​a particle initally at rest moves along x-axis under acceleration  a=2t/s2 then velocity at 2 s of motion is

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Let us assume that,acceleration ,a=2t+5a=dvdtdvdt=2t+5dv=2t+5dtIntegrating both side, we get,0vdv=022t+5dtv=2t22+5t02v=22+5×2v=4+10=14 m/s

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