A particle is acted upon by a constant force f1 =2i -3 j+ 4k and F2 =-i+2j-3k is displaced from the point A(2,1,0) to the point B (-3,-4.2) find the total work done by these force
Dear students
Net force acts on particle F = F1 + F2 = 2i -3 j+ 4k -i+2j-3k = i -j+k
Displacement r = B - A = -3i -4 j+ 2k - 2 i-1j-0k = -5i -5j +2k
Total Workdone = F.r = ( i -j+k) . -5i -5j +2k = -5 +5+2 = 2 J
Regards
Vijaya
Net force acts on particle F = F1 + F2 = 2i -3 j+ 4k -i+2j-3k = i -j+k
Displacement r = B - A = -3i -4 j+ 2k - 2 i-1j-0k = -5i -5j +2k
Total Workdone = F.r = ( i -j+k) . -5i -5j +2k = -5 +5+2 = 2 J
Regards
Vijaya