A Particle is projected from the ground in earth’s gravitational field at an angle theta with the horizontal then Center of curvature of projectile’s trajectory at the highest point is below the ground level if theta < tan-1 √2 / is above the ground level if theta > tan-1 √2 / may be above the ground level if theta < tan-1 √2./ may be above the ground level if theta < tan-1 √2./ below the ground level if theta > tan-1 √2.
Dear student,
At height point of trajectory, velocity of particle is,
If we compare particles motion at this point with circular motion, we can write equation of motion as,
Where, r is radius of curvature.
Height of projectile is,
If centre of curvature is below ground level,
So, correct option is (a).
Regards.
At height point of trajectory, velocity of particle is,
If we compare particles motion at this point with circular motion, we can write equation of motion as,
Where, r is radius of curvature.
Height of projectile is,
If centre of curvature is below ground level,
So, correct option is (a).
Regards.