A particle is projected vertically upwards with velocity 2 m/s and a second particle is projected at the same instant - Physics -

Question

A particle is projected vertically upwards with velocity 2 m/s and
a second particle is projected at the same instant (at a height 20
m above the first particle) with the same velocity 2m/s at an angle
of projection 30° Find the time ( in second) after projection
when the distance between them is minium

Vara · Accepted Answer

Expression for the time after projection when the distance between
them is minimum:

t=h2vHere,h is initial distance between the two particlesv is velocity of each particlet=2022 = 5 sNote: The time taken is independent of the angle of projection of the second