a particle is projected with a velocity u at an angle theta with the horizontal at any instant its velocity v is at right angles to it's initial velocity u then v is:-
a. u cos theta b. u tan theta c. u cot theta d. u sec theta

I want answer with full solution.


When projectile is projected with velocity U and it aquires velocity V when projectile makes angle 90° with the direction of of velocity U.HORIZONTAL velocity of projectile= U cosθ.horizontal velocitywhen projectile makes an angle of 90° with the direction of velocityU is given by V cos90-θ as shown in the diagram.But horizontal velocities of projectile motion remain the same i. e.U cosθ =V cos90-θ     or   U cosθ =V sinθ         or      V= U cotθ.

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c.
when its velocity is v then v cos(90-@)=ucos@
​as horizontal component of velocity remains same.

 
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