A particle is thrown vertically upward with initial velocity of 60 m/s. The distance covered by the particle in first 2 seconds of descent will be?

As v= u+at,
T=v-u/a=0-60/-10= 6sec
The distance covered
Upward speed,
S= u?t+1/2at^2
Time,t= 6-2=4sec
Down speed,
After this add the values and then find total distance covered by adding upward speed and downward speed then subtarct upward speed and downward speed and you will get displacement.
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