A particle moves along a parabolic path, y=9x^2 in such a way that x component of velocity remain constant and has value 1/3 m/s. Find the acceleration of the projectile.

Dear Student,

Given:  y =9x2velocity is given by:dydt = 9*2 xdxdtdydt = 18xdxdtas x component of the velocity remains constant i.e.Vx= dxdt = 13Vy = (18*13)xVy = 6xAcceleration is given by:ay =dVydt = 6dxdtay = 6*13ay = 2

Acceleration has only y component, so acceleration of the particle is in y direction
i.e.
a = ax i^ + ayja = (0) i^ + 2ja = 2j


Regards

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