A particle moving with SHM has speeds 3cm/s and 4cm/s at displacements 8cm and 6cm respectively,from the equilibrium position.Find - (1) Time period of the oscillations (2)​Amplitude of the oscillations

Sol: Velocity of a particle during SHM is given by following formula:
                                   v = ωA2-x2where:A = Amplitudex = displacement from mean position(1). As per given that: v = 3 cmsec at x = 8 cmso3 = ωA2-823 = ωA2-64                         .....(1)(2). As per given thatv = 4 cmsec at x = 6 cmso4 = ωA2-624 = ωA2-36                         .....(2)dividing eq ..(2) by (1)169 = A2-36A2-6416A2-16×64 = 9A2-36×97A2 = 1024-324 = 700A = ±10So the value of amplitude will be:A = 10 cm                                        ....(3)now putting value of eq ..(3) in ..(1)3 = ω102-643 = ω100-643 = ω×6ω = 12so the time period will be given as:T = 2πωT = 2π12T = 4π sec.

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