A particle of charge 1micro coulomb and mass 1gm moving with velocity 4m/s is subjected to a uniform electric field of magnitude 300 V/m for 10sec then its final speed cannot be


Dear Student,
                     

                         Let the final speed is v by first equation of motion we know            v=u+αt                           ttime=10s              uinitial velocity              αaccelaration of the particale    which is  given by                 α =  qEm         E electric field,q charge  on particale           
hence final velocity    v=u+qEmtput values of known parametersv=4+1×10-6×3001×10-3×10=7m/s
Regard

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