A particle of mass 2 kg is at rest initially. A force of magnitude F is applied on the particle such that the particle starts moving along the X - axis and its displacement is given by x = 2 + 3t + 4t? . calculate the magnitude of i) the velocity of the particle at t = 3s ii) acceleration of the particle at t = 3s iii)force(F) applied on the particle Share with your friends Share 0 Sanat K Mukherjee answered this Given, Mass of the particle, m = 2 kg displacement pf the particle provided in the question is x = 2 + 3t + 4tIt must bex = 2 + 3t + 4t2 or x = 2 + 3t2 + 4t (otherwise the displaement must have been stated x=2+7t)Assuming x = 2 + 3t + 4t2, the question is soled as follows: i) velocity, v=dxdt=3+8tAt, t=3s, v=3+24=27m/sii) Acceleration, a=dvdt=8acceleration remains constant and its value at all times including t=3s is 8m/s2iii) Force applied on the particle, F=ma=2×8=16N Regards 0 View Full Answer