A particle projected with velocity 50m/s at an angle 60with horizontal .The time after which the velocity will make 45 degree with horizontal is
Applying the equation,
t = v(sin$-cos$)/g we get,
t = 50(sin60-cos45)/10
t= 50(?3/2- 1/2)/10
on solving we get,
t= 2.5?0.73
t = 1.825 which is approx. 1.83.
Hope you get it!
t = v(sin$-cos$)/g we get,
t = 50(sin60-cos45)/10
t= 50(?3/2- 1/2)/10
on solving we get,
t= 2.5?0.73
t = 1.825 which is approx. 1.83.
Hope you get it!